php准确计算复活节日期的方法_PHP教程

php准确计算复活节日期的方法

2020-09-20 14:49php教程网 PHP教程

这篇文章主要介绍了php准确计算复活节日期的方法,涉及php操作日期的技巧,非常具有实用价值,需要的朋友可以参考下

本文实例讲述了php准确计算复活节日期的方法。分享给大家供大家参考。具体如下：

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									<?PHP

									function isLeapYear( $nYEAR ) {

									 if((($nYEAR % 4 == 0) AND !($nYEAR % 100 == 0)) AND ($nYEAR % 400 != 0))

									 {

									  return TRUE;

									 } else {

									  return FALSE;

									 }

									}

									function div( $a, $b ){

									 return( $a - ( $a % $b )) / $b;

									}

									function easterSunday( $nYEAR ) {

									 // The function is able to calculate the date 

									 //of eastersunday back to the year 325,

									 // but mktime() starts at 1970-01-01!

									 if ( $nYEAR < 1970 ) {

									  $dtEasterSunday = mktime( 1,1,1,1,1,1970 );

									 } else {

									  $nGZ = ( $nYEAR % 19 ) + 1;

									  $nJHD = div( $nYEAR, 100 ) + 1;

									  $nKSJ = div( 3 * $nJHD, 4 ) - 12;

									  $nKORR = div( 8 * $nJHD + 5, 25 ) - 5;

									  $nSO = div( 5 * $nYEAR, 4 ) - $nKSJ - 10;

									  $nEPAKTE = (( 11 * $nGZ + 20 + $nKORR - $nKSJ ) % 30 );

									  if (( $nEPAKTE == 25 OR $nGZ == 11 ) AND $nEPAKTE == 24 ) {

									   $nEPAKTE = $nEPAKTE + 1;

									  }

									  $nN = 44 - $nEPAKTE;

									  if( $nN < 21 ) {

									   $nN = $nN + 30;

									  }

									  $nN = $nN + 7 - (( $nSO + $nN ) % 7 );

									  $nN = $nN + isLeapYear( $nYEAR );

									  $nN = $nN + 59;

									  $nA = isLeapYear( $nYEAR );

									  // Month

									  $nNM = $nN;

									  if ( $nNM > ( 59 + $nA )) {

									   $nNM = $nNM + 2 - $nA;

									  }

									  $nNM = $nNM + 91;

									  $nMONTH = div( 20 * $nNM, 611 ) - 2;

									  // Day

									  $nNT = $nN;

									  $nNT = $nN;

									  if ( $nNT > ( 59 + $nA )) {

									   $nNT = $nNT + 2 - $nA;

									  }

									  $nNT = $nNT + 91;

									  $nM = div( 20 * $nNT, 611 );

									  $nDAY = $nNT - div( 611 * $nM, 20 );

									  $dtEasterSunday = mktime( 0,0,0,$nMONTH,$nDAY,$nYEAR );

									 }

									 return $dtEasterSunday;

									}

									?>