服务器之家:专注于服务器技术及软件下载分享
分类导航

Mysql|Mssql|Oracle|Redis|

服务器之家 - 数据库 - Mysql - MySQL 查找价格最高的图书经销商的几种SQL语句

MySQL 查找价格最高的图书经销商的几种SQL语句

2019-10-30 17:41mysql教程网 Mysql

不同的图书,在不同的经销商的价格不同,我们这里要找到每种图书最高的经销商是谁? 找最低的类似了。

mysql> use test; 
Database changed 
mysql> CREATE TABLE shop ( 
-> article INT(4) UNSIGNED ZEROFILL DEFAULT '0000' NOT NULL, 
-> dealer CHAR(20) DEFAULT '' NOT NULL, 
-> price DOUBLE(16,2) DEFAULT '0.00' NOT NULL, 
-> PRIMARY KEY(article, dealer)); 
Query OK, 0 rows affected (0.13 sec) 

mysql> INSERT INTO shop VALUES 
-> (1,'A',3.45),(1,'B',3.99),(2,'A',10.99),(3,'B',1.45), 
-> (3,'C',1.69),(3,'D',1.25),(4,'D',19.95); 
Query OK, 7 rows affected (0.03 sec) 
Records: 7 Duplicates: 0 Warnings: 0 

mysql> select * from shop; 
+---------+--------+-------+ 
| article | dealer | price | 
+---------+--------+-------+ 
| 0001 | A | 3.45 | 
| 0001 | B | 3.99 | 
| 0002 | A | 10.99 | 
| 0003 | B | 1.45 | 
| 0003 | C | 1.69 | 
| 0003 | D | 1.25 | 
| 0004 | D | 19.95 | 
+---------+--------+-------+ 
7 rows in set (0.06 sec) 

mysql> select article,max(price) from shop group by article 
-> ; 
+---------+------------+ 
| article | max(price) | 
+---------+------------+ 
| 0001 | 3.99 | 
| 0002 | 10.99 | 
| 0003 | 1.69 | 
| 0004 | 19.95 | 
+---------+------------+ 
4 rows in set (0.05 sec) 

mysql> select article,max(price),dealer from shop group by article; 
+---------+------------+--------+ 
| article | max(price) | dealer | 
+---------+------------+--------+ 
| 0001 | 3.99 | A | 
| 0002 | 10.99 | A | 
| 0003 | 1.69 | B | 
| 0004 | 19.95 | D | 
+---------+------------+--------+ 
4 rows in set (0.00 sec) 

mysql> select article,dealer,price from shop s1 
-> where price=(select max(s2.price) from shop s2 
-> where s1.article=s2.article); 
+---------+--------+-------+ 
| article | dealer | price | 
+---------+--------+-------+ 
| 0001 | B | 3.99 | 
| 0002 | A | 10.99 | 
| 0003 | C | 1.69 | 
| 0004 | D | 19.95 | 
+---------+--------+-------+ 
4 rows in set (0.01 sec) 

mysql> select s1.article,dealer,s1.price 
-> from shop s1 
-> join( 
-> select article,max(price) as price from shop 
-> group by article) as s2 
-> on s1.article = s2.article and s1.price = s2.price; 
+---------+--------+-------+ 
| article | dealer | price | 
+---------+--------+-------+ 
| 0001 | B | 3.99 | 
| 0002 | A | 10.99 | 
| 0003 | C | 1.69 | 
| 0004 | D | 19.95 | 
+---------+--------+-------+ 
4 rows in set (0.05 sec) 

mysql> select s1.article,s1.dealer,s1.price from shop s1 
-> left join shop s2 on s1.article=s2.article and s1.price select s1.article,s1.dealer,s1.price,s2.* from shop s1 left join shop s2 
on s1.article=s2.article and s1.price

延伸 · 阅读

精彩推荐